Answer
$x=\frac{\pi}{4}$ and $x=\frac{5\pi}{4}$
Work Step by Step
$sin~x-2=cos~x-2$
$sin~x=cos~x-2+2$
$sin~x=cos~x$
$\frac{sin~x}{cos~x}=1$
$tan~x=1$
The solutions in the interval $[0,2\pi)$ are:
$x=\frac{\pi}{4}$ and $x=\frac{5\pi}{4}$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 7 - 7.3 - Solving Trigonometric Equations - 7.3 Exercises - Page 530: 29
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