Answer
True.
It is because $csc~60°=\frac{1}{sin~60°}$
Work Step by Step
$sin~60°=\frac{\sqrt 3}{2}$ (See the table on page 436)
$csc~60°=\frac{1}{sin~60°}=\frac{1}{\frac{\sqrt 3}{2}}=\frac{2}{\sqrt 3}$
So:
$sin~60°csc~60°=\frac{\sqrt 3}{2}\frac{2}{\sqrt 3}=1$
