Answer
$x=0$
Work Step by Step
$\log_8(x-1)=\log_8(x-2)-\log_8(x+2)$
$\log_8(x-1)=\log_8(\frac{x-2}{x+2})$
Using the one-to-one property:
$x-1=\frac{x-2}{x+2}$
$x^2+x-2=x-2$
$x^2=0$
$x=0$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 5 - Review Exercises - Page 414: 95
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