Answer
$\ln x-[\ln(x+1)+\ln(x-1)]=\ln\frac{x}{x^2-1}$
Work Step by Step
$\ln x-[\ln(x+1)+\ln(x-1)]=\ln x-\ln[(x+1)(x-1)]=\ln x-\ln(x^2-1)=\ln\frac{x}{x^2-1}$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 5 - 5.3 - Properties of Logarithms - 5.3 Exercises - Page 386: 71
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