Answer
$100~decibels$
Work Step by Step
$\beta=10\log\frac{I}{10^{-12}}$
If $I=10^{-2}$:
$\beta=10\log\frac{10^{-2}}{10^{-12}}$
$\beta=10\log10^{-2+12}=10\log10^{10}$
$\beta=10\times10=100$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 5 - 5.2 - Logarithmic Functions and Their Graphs - 5.2 Exercises - Page 380: 84b
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