Answer
$8 \sqrt 6$
Work Step by Step
$(x-h)^2=4p(y-k)$
or, $(4-0)^2=4p(10-12)$
or, $p=-2$
Now, $x^2=-8(y-12)$
or, $x^2=-8(0-12)$
$x=4 \sqrt 6$
The width at ground level is $2x= 8 \sqrt 6$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 4 - Review Exercises - Page 354: 85
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