Answer
$y=1+\dfrac{2}{x-2}$
Work Step by Step
$m=\dfrac{y-1}{0-2}=\dfrac{1-0}{2-x}$
So, $\dfrac{y-1}{-2}=\dfrac{1}{2-x}$
and $y-1=\dfrac{2}{x-2}$
$\implies y=1+\dfrac{2}{x-2}$
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