Answer
True.
We can have a rational function whose denominator has as many zeroes as we want.
Work Step by Step
For example:
$y=\frac{1}{(x-1)(x-2)(x-3)..(x-1000)(x-1001)(x-1002)...}$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 4 - 4.1 - Rational Functions and Asymptotes - 4.1 Exercises - Page 317: 47
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