Answer
Domain: X is on the interval ($-\infty$, -4) U (-4, $\infty$)
Work Step by Step
A denominator cannot be zero, so the domain is all real numbers except the x value where the denominator is 0.
In this problem the denominator is $x^{2}$ + 8x + 16, so:
$x^{2}$ + 8x + 16 = 0
This can be factored into:
(x + 4)(x + 4) = 0
x = -4
Therefore, the domain is all real numbers except where x = -4.
