Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 3 - P.S. Problem Solving - Page 308: 12a

Answer

$A=\frac{x^2}{16}+\frac{10000-200x+x^2}{4\pi}=\frac{(4+\pi)x^2-800x+40000}{16\pi}$

Work Step by Step

The length of each side of the square: $\frac{x}{4}$ The area of the square: $A=(\frac{x}{4})^2=\frac{x^2}{16}$ The length of the wire used to form the circle: $100-x=2\pi r$ $r=\frac{100-x}{2\pi}$ The area of the circle: $A=\pi r^2=\pi(\frac{100-x}{2\pi})^2=\frac{(100-x)^2}{4\pi}=\frac{10000-200x+x^2}{4\pi}$ The combined area: $A=\frac{x^2}{16}+\frac{10000-200x+x^2}{4\pi}=\frac{(4+\pi)x^2-800x+40000}{16\pi}$
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