Answer
Mathematical model:
$F=1833.33x$
If $x=0.16~m$:
$F=293.33~N$
Work Step by Step
Applied force: $F$
Distance: $x$
$F=kx$
When $x=0.12~m$, $F=220~N$
$220=k(0.12)$
$k=\frac{220}{0.12}=1833.33~\frac{N}{m}$
Mathematical model:
$F=1833.33x$
If $x=0.16~m$:
$F=1833.33\times0.16=293.33~N$