Answer
$b=±10$
Work Step by Step
The $y$ of the vertex is $-50$:
$f(-\frac{b}{2a})=-50$
$f(-\frac{b}{2})=-50$
$(-\frac{b}{2})^2+b(-\frac{b}{2})-25=-50$
$\frac{b^2}{4}-\frac{b^2}{2}=-25$
$-\frac{b^2}{4}=-25$
$b^2=100$
$b=±10$
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