Answer
$x+2$
Domain of the function $f$ is: $[ 2, \infty)$.
Domain of the inverse of function $f$ is: $[0, \infty)$.
Work Step by Step
We have $y=|x-2|=x-2$
or, $x=y-2$
or, $y=x+2$
Replace $y$ with $f^{-1} (x)$.
so, $f^{-1} (x)=x+2$