Answer
a) $(-2a,2c)$
b) $(-2a,-2c)$
Work Step by Step
An even function is when $f(-x)=f(x)$ for all $x$.
An odd function is when $f(-x)=-f(x)$ for all $x$.
a) Hence if $(2a,2c)$ is on the function, then $f(-2a)=2c$ by the evenness of the function. Thus $(-2a,2c)$ is also a point.
b) Hence if $(2a,2c)$ is on the function, then $f(-2a)=-2c$ by the oddness of the function. Thus $(-2a,-2c)$ is also a point.
