Answer
$L_{1}$ and $L_{2}$ are both horizontal lines, so they are parallel.
Work Step by Step
$$L_{1}: (-6, -3), (2,-3)$$
$m_{1}=\frac{-3-(-3)}{2-(-6)}$
$m_{1}=\frac{0}{8}=0$
$$L_{2}: (3, -\frac{1}{2}), (6, -\frac{1}{2})$$
$m_{2}=\frac{-\frac{1}{2}-(-\frac{1}{2})}{6-3}$
$m_{2}=\frac{0}{3}=0$