Answer
$n=10$
Work Step by Step
$_{n}P_k=\frac{n!}{(n-k)!}$
Hence here $_{n}P_4=\frac{n!}{(n-4)!}=10_{n-1}P_3=10\frac{(n-1)!}{((n-1)-3)!}\\\frac{n!}{(n-4)!}=10\frac{(n-1)!}{(n-4)!}\\n(n-1)(n-2)(n-3)=10(n-1)(n-2)(n-3)\\n=10$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 11 - 11.6 - Counting Principles - 11.6 Exercises - Page 825: 81
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