Answer
$61176$
Work Step by Step
The sum of the fifth powers of the first $n$ integers can be obtained by the following formula: $\frac{n^2(n+1)^2(2n^2+2n-1)}{12}.$
Thus the sum:$\frac{8^2(8+1)^2(2(8)^2+2(8)-1)}{12}=\frac{64(81)(143)}{12}=61176$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 11 - 11.4 - Mathematical Induction - 11.4 Exercises - Page 807: 50
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