Answer
See below.
Work Step by Step
As we can see, the sums of the first $n$ consecutive odd integers is $n^2$.
$1+3+5+7+9+11=36=6^2$
$1+3+5+7+9=25=5^2$
$1+3+5+7=16=4^2$
$1+3+5=9=3^2$
$1+3=4=2^2$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 11 - 11.2 - Arithmetic Sequences and Partial Sums - 11.2 Exercises - Page 788: 87c
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