Answer
$∑(x_i-x ̅ )=0$
Work Step by Step
$\frac{1}{n}∑x_i=x ̅ $
$∑x_i=nx ̅ $
$∑x ̅=x ̅ +x ̅ +x ̅ +...+x ̅ =nx ̅ $
$∑(x_i-x ̅ )=∑x_i-∑x ̅=nx ̅ -nx ̅ =0$
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