Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 10 - 10.1 - Matrices and Systems of Equations - 10.1 Exercises - Page 712: 91

Answer

$f(x) = x^{2} + 2x + 5$

Work Step by Step

We must first solve for the functions in terms of a, b, and c: f(1) = a + b + c = 8 f(2) = 4a + 2b + c = 13 f(3) = 9a + 3b + c = 20 We can then form the matrix, and use Gaussian elimination and back-substitution to solve the matrix: $\begin{bmatrix} 1 & 1 & 1 & |8\\ 4 & 2 & 1 & |13\\ 9 & 3 & 1 & |20\\ \end{bmatrix}$ ~ $\begin{bmatrix} 1 & 1 & 1 & |1\\ 0 & -2 & -3 & |-19\\ 0 & -6 & -8 & |-52\\ \end{bmatrix}$ ~ $\begin{bmatrix} 1 & 1 & 1 & |8\\ 0 & 2 & 3 & |19\\ 0 & -6 & -8 & |-52\\ \end{bmatrix}$ ~ $\begin{bmatrix} 1 & 1 & 1 & |8\\ 0 & 2 & 3 & |19\\ 0 & 0 & 1 & |5\\ \end{bmatrix}$ C: c = 5 B: 2b + 3(5) = 19 2b + 15 = 19 2b = 4 b = 2 A: a + 2 + 5 = 8 a + 7 = 8 a = 1 Using the solution above, the quadratic function is: $f(x) = x^{2} + 2x + 5$
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