Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 10 - 10.1 - Matrices and Systems of Equations - 10.1 Exercises - Page 711: 63

Answer

x = -4 y = -3 z = 6

Work Step by Step

Gaussian Elimination: $\begin{bmatrix} 1 & 2 & -3 & |-28\\ 0 & 4 & 2 & |0\\ -1 & 1 & -1 & |-5\\ \end{bmatrix}$ ~ $\begin{bmatrix} 1 & 2 & -3 & |-28\\ 0 & 2 & 1 & |0\\ 0 & 3 & -4 & |-33\\ \end{bmatrix}$ ~ $\begin{bmatrix} 1 & 2 & -3 & |-28\\ 0 & 2 & 1 & |0\\ 0 & 0 & -11 & |-66\\ \end{bmatrix}$ Back-Substitution: Z: -11z = -66 z = 6 Y: 2y + (1)6 = 0 2y = -6 y = -3 X: x + 2(-3) - 3(6) = -28 x - 6 - 18 = -28 x - 24 = -28 x = -4 In Total: x = -4 y = -3 z = 6
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