Answer
x = 2, 3
Work Step by Step
Solve the individual equaions obtained after breaking the expression into two separate equations.
Case 1:
$x^2-6 = -x$
$x^2+x-6=0$
(x+3)(x-2)=0
Plug in the Case 1 equation to see -3 is an extraneous solution. Hence x=2.
Case 2:
$x^2-6 = x$
$x^2-x-6=0$
(x-3)(x+2)=0
Plug in the Case 2 equation to see -2 is an extraneous solution. Hence x=3.
