Answer
a)no
b)yes
c)yes
d)no
Work Step by Step
We can check whether they solve the inequality by plugging in the different values and seeing if they satisfy the inequality:
a) $\frac{3(-2)^2}{(-2)^2+4}=\frac{12}{8}\gt1$, thus no
b) $\frac{3(-1)^2}{(-1)^2+4}=\frac{3}{5}\lt1$, thus yes
c) $\frac{3(0)^2}{(0)^2+4}=\frac{0}{4}\lt1$, thus yes
d) $\frac{3(3)^2}{(3)^2+4}=\frac{27}{13}\gt1$, thus no