Answer
It was during the years of 2005 and 2006.
Work Step by Step
$30\leq W\leq32$
$30\leq 0.903t+26.08\leq32$
$30-26.08\leq 0.903t+26.08-26.08\leq32-26.08$
$3.92\leq 0.903t\leq5.92$
$\frac{3.92}{0.903}\leq\frac{0.903t}{0.903}\leq\frac{5.92}{0.903}$
$4.341\leq t\leq6.556$
So, the solutions are: $t=5$ and $t=6$. It corresponds to the years 2005 and 2006.