Answer
$|x+1|\leq4$
Work Step by Step
$|u|\lt a~↔~-a\lt u\lt a$
$|u|\leq a~↔~-a\leq u\leq a$
$|u|\gt a~↔~u\lt-a~or~u\gt a$
$|u|\geq a~↔~u\leq-a~or~u\geq a$
$-5\leq x\leq3$
$-5+1\leq x+1\leq3+1$
$-4\leq x+1\leq4$
$|x+1|\leq4$
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