Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 1 - 1.6 - Other Types of Equations - 1.6 Exercises - Page 129: 75

Answer

$x=1.038,x=-1.038$

Work Step by Step

Let $a=x^2$. We get, $3.2a^2-1.5a-2.1=0$ Using quadratic formula, $a=\frac{-(-1.5)\pm \sqrt{(-1.5)^2-4 (3.2)(-2.1)}}{2\cdot (3.2)}$ On solving, $a=-0.6089,1.0777$ Now, let's solve for $x$. Since we need only real solutions of $x$, we only need to find $x$ for $a=1.0777$ $\implies x^2=1.0777$ $\implies x=\pm 1.038$
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