Cha658pter 9 - 9.3 - Multivariable Linear Systems - 9.3 Exercises - Page 658: 11

$x=-13; y=-10; z=8$

Plug the value of $z=8$ into $y+2z=6$ $y+2(8)=6 \implies y=-10$ Now, we will plug the value of $y$ and $z$ into the expression of $x$ to find the value of $x$. We get: $x-(-10)+5(8)=37 \implies x=-13$ Thus, $x=-13; y=-10; z=8$