Answer
No real solution
Work Step by Step
To complete the square, we add $(b/2)^2$ to both sides and subtract the constant.
$(-4/2)^2 = 4$
$x^2 -4x + 4 = -3$
A square cannot be negative, so this has no real solution
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 9 Quadratic Relations and Conic Sections - Prerequisite Skills - Page 612: 8
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