Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 9 Quadratic Relations and Conic Sections - Chapter Test - Page 673: 4

Answer

$$\left(\frac{5}{2},\:-2\right)$$

Work Step by Step

Using the distance formula, we find: $$=\sqrt{\left(3-2\right)^2+\left(1-\left(-5\right)\right)^2}\\ \sqrt{37}$$ Using the midpoint formula, we find: $$\left(\frac{3+2}{2},\:\frac{1-5}{2}\right)\\ \left(\frac{5}{2},\:-2\right)$$
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