Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 9 Quadratic Relations and Conic Sections - Chapter Review - Page 669: 5

Answer

$$\left(-2,\:-4\right)$$

Work Step by Step

Using the distance formula, we find: $$\sqrt{\left(2-\left(-6\right)\right)^2+\left(-3-\left(-5\right)\right)^2}\\ 2\sqrt{17}$$ Using the midpoint formula, we find: $$\left(\frac{2-6}{2},\:\frac{-3-5}{2}\right)\\ \left(-2,\:-4\right)$$
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