Chapter 9 Quadratic Relations and Conic Sections - 9.7 Solve Quadratic Systems - 9.7 Exercises - Skill Practice - Page 661: 14

no solution.

Substituting the transformed version of the first equation ($y=6+3x$) into the second one we get: $8x+(6+3x)^2+24=0\\8x+(36+36x+9x^2)+24=0\\9x^2+44x+60=0$ This has a negative discriminant ($44^2-4(9)(60)=-224)$. Thus there is no solution.