Answer
See below
Work Step by Step
Given $x^2-10x+4y=0$
We can see that $a=1\\b=0\\c=0$
We will find the discriminant of the given equation $=b^2-4ac\\=0^2-4(-1)(9)\\=0$
The conic is a parabola.
To graph the hyperbola, first complete the square in x.
$x^2-10x+4y=0\\x^2-10x+25-25=-4y\\(x-5)^2=-4y+25\\(x-5)^2=-4(y-6.25)$
From the equation, you can see that the vertex is at $(5,6.25)$.
From the graph, the highest point of the jump is at $6.25 ft $. The jump is 10ft long.
