Answer
See below
Work Step by Step
The equation in standard form
$$18x^2+18y^2=288\\x^2+y^2=16$$
The equation for a circle with the center at the origin is $x^2+y^2=r^2$
Find $r^2=16$
Hence, $r= 4$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 9 Quadratic Relations and Conic Sections - 9.5 Graph and Write Equations of Hyperbolas - 9.5 Exercises - Skill Practice - Page 646: 32
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