Answer
See below
Work Step by Step
Rewrite the equation in standard form
$$\frac{y^2}{49}-\frac{x^2}{121}=1$$
The denominator of $x^2$ is smaller than $y^2$, so the transverse axis is vertical.
Identify the vertices, foci, and asymptotes. Note that $a=7$ and
$b=11$. The $y^2-term$ is positive, so the transverse axis is vertical and the vertices are at $(0,\pm 7)$. Find the foci:
$c^2=a^2+b^2=7^2+11^2=170\\
\rightarrow c=\sqrt 170$
The foci are at $(0,\pm \sqrt 170)$
The asymptotes are $y=\pm \frac{7}{11}x$
Draw the hyperbola.
