Answer
See below
Work Step by Step
The foci and vertices lie on the y-axis equidistant from the origin, so the transverse axis is vertical and the center is the origin. The foci are $c=3$ and $a=1$.
Find $b^2=c^2-a^2=3^2-1^2=8$
$b=\sqrt 8$
Because the transverse axis is vertical, the standard form of the equation is as follows:
$$\frac{y^2}{1}-\frac{x^2}{8}=1$$