Chapter 9 Quadratic Relations and Conic Sections - 9.3 Graph and Write Equations of Circles - 9.3 Exercises - Skill Practice - Page 630: 39

$$ x^2+y^2=260$$

Since the center is at the origin, we use the distance formula to find that the radius must be: $$\sqrt{\left(-8-0\right)^2+\left(14-0\right)^2} = 2\sqrt{65}$$ Thus, it follows: $$x^2+y^2=r^2 $$ $$ x^2+y^2=260$$