Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 9 Quadratic Relations and Conic Sections - 9.2 Graph and Write Equations of Parabolas - 9.2 Exercises - Skill Practice - Page 624: 38

Answer

Answer $A$: $y^2=-32x$

Work Step by Step

Because the parabola has the vertex at $(0,0)$ it has one of the following equations: $$\begin{align*} x^2&=4py\\ y^2&=4px. \end{align*}$$ Because the focus lies on the $x$-axis, the parabola has horizontal axis of symmetry and its equation is: $$y^2=4py.$$ Using the focus $(p,0)=(-8,0)$ we determine $p$: $$p=-8.$$ The equation of the parabola is: $$y^2=-32x.$$ The correct answer is Answer $A$.
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