Answer
7
Work Step by Step
Solving the equation using the rules of Algebra, we find:
$$\left(\sqrt{x-3}\right)^2=\left(x-5\right)^2 \\ x-3=x^2-10x+25 \\ x=7,\:x=4$$
We see that $x=4$, however, is extraneous, so it is not a solution.
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 9 Quadratic Relations and Conic Sections - 9.1 Apply the Distance and Midpoint Formulas - 9.1 Exercises - Mixed Review - Page 619: 72
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