Answer
-1
Work Step by Step
For cross multiplication, we know:
$$\frac{a}{d} =\frac{b}{c} \rightarrow ac=bd$$
Thus, we find:
$$\left(x-3\right)\left(x+2\right)=\left(x+5\right)x\\ x^2-x-6=x^2+5x\\ \\ x^2-x-6=x^2+5x \\ x=-1$$
Checking our solution by plugging the given value back into the equation, we assure that the solutions are not extraneous.
