Answer
No solution.
Work Step by Step
For cross multiplication, we know:
$$\frac{a}{d} =\frac{b}{c} \rightarrow ac=bd$$
Thus, we find:
$$\frac{\left(3x+6\right)}{x^2-4}=\frac{\left(x+1\right)}{x-2}\\ \frac{3}{x-2}\left(x-2\right)=\frac{x+1}{x-2}\left(x-2\right)\\ x=2$$
Checking our solution by plugging the given value back into the equation, we assure that the solution IS extraneous.
