Answer
$$\frac{x^2y^2}{4}$$
Work Step by Step
Using the rules of exponents and cancelling common factors in the numerator and the denominator, we find:
$$\frac{3x^5y^2\times \:6xy^2}{8xy\times \:9x^3y} \\ \frac{18x^5y^4}{8\times \:9x^3yy} \\ \frac{y^4x^{5-3}}{4y^2} \\ \frac{x^2y^{4-2}}{4} \\ \frac{x^2y^2}{4}$$