Answer
$$\frac{4\left(x+4\right)\left(x+5\right)}{x}$$
Work Step by Step
Using the rules of exponents and cancelling common factors in the numerator and the denominator, we find:
$$\frac{4\left(x+5\right)}{x\left(x+4\right)}\left(x^2+8x+16\right)\\ \frac{4\left(x+4\right)^2\left(x+5\right)}{x\left(x+4\right)}\\ \frac{4\left(x+4\right)\left(x+5\right)}{x}$$
