Answer
$50.21
Work Step by Step
The average amount paid per ticket can be obtained by: $\frac{S}{A}=\frac{\frac{-6420t+292000}{6.02t^2-125t+1000}}{\frac{-407t+7220}{5.92t^2-131t+1000}}$
For 1999, plug in $t=7$: $\frac{S}{A}=\frac{\frac{-6420(7)+292000}{6.02(7)^2-125(7)+1000}}{\frac{-407(7)+7220}{5.92(7)^2-131(7)+1000}}\approx 50.21$