Answer
$y=axz^2$; $a$ is a constant of variation.
Work Step by Step
$z^2=\dfrac{1}{a} \dfrac{y}{x}$
We rearrange to get $y=axz^2$;
Here $a$ is a constant of variation.
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 8 Rational Functions - 8.1 Model Inverse and Joint Variation - 8.1 Exercises - Skill Practice - Page 556: 32
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