Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 8 Rational Functions - 8.1 Model Inverse and Joint Variation - 8.1 Exercises - Problem Solving - Page 557: 41b

Answer

$6.674 \times 10^{-11} N m^2 /kg^2 $

Work Step by Step

From the previous part (a), we have $F= G\dfrac{m_1m_2}{d^2}$ Re-arrange as: $G=\dfrac{Fd^2}{m_1m_2}$ Plugging in the data, we have $G=\dfrac{(3.53 \times 10^{22}) (1.5 \times 10^{11})^2}{1.99 \times 10^{30} (5.98 \times 10^{24})} \approx 6.674 \times 10^{-11} N m^2 /kg^2 $
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