Answer
See below
Work Step by Step
Given: $9^{2x+1}=3^{5x-1}$
Solve for $x$: $\ln 9^{2x+1}=\ln 3^{5x-1}\\(2x+1)\ln 9=(5x-1)\ln 3\\(2 \ln 9)x+\ln 9=(5\ln 3)x-\ln 3\\(2\ln 9-5\ln 3)x=-\ln 3-\ln 9\\x=\frac{-\ln 3-\ln 9}{2\ln 9-5\ln 3}=3$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 7 Exponential and Logarithmic Functions - Standardized Test Practice - Gridded Answer - Page 547: 14
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