Answer
See below
Work Step by Step
From part a, $E=e^{0.05}-1$
From part b, $E=e^{0.1}-1$
Obtain: $\frac{e^{0.1}-1}{e^{0.05}-1}\\=\frac{(e^{0.05})^2-1}{e^{0.05}-1}\\=\frac{(e^{0.05}-1)(e^{0.05}+1)}{e^{0.05}-1}\\=e^{0.05}+1$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 7 Exponential and Logarithmic Functions - Mixed Review of Problem Solving - Lessons 7.5-7.7 - Page 537: 5c
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