Answer
See below
Work Step by Step
Given $A=P(1+\frac{r}{n})^{nt}$
and $n=12$
For $P=1500, r=0.02$, $A=1500(1+\frac{0.02}{12})^{12(3)}=1592.68$
For $P=2000, r=0.03$, $A=1500(1+\frac{0.03}{12})^{12(5)}=2323.23$
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