Answer
$$ \frac{log23}{log6} \approx 1.750 $$
Work Step by Step
Using the change of base formula, we find:
$$log_6(23) = \frac{log23}{log6}$$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 7 Exponential and Logarithmic Functions - Chapter Test - Page 543: 20
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