Answer
$y=2\cdot x^{\ln_6{3.5}}$
Work Step by Step
Let $y=ax^b$.
Then our equations are: $2=a1^b$ and $7=a6^b$.
Then $2=a$.
Then: $7=26^b\\3.5=6^b\\b=\ln_6{3.5}$.
Thus $y=2\cdot x^{\ln_6{3.5}}$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 7 Exponential and Logarithmic Functions - 7.7 Write and Apply Exponential and Power Functions - Guided Practice for Example 4 - Page 531: 5
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
